Answer: The percent concentration ( % m/v) of dextrose in the solution is 2 %
Explanation:
We are given:
Mass of Yeast Extract = 5.0 grams
Mass of [tex]K_2HPO_4[/tex] = 1.0 grams
Mass of [tex]MgSO_4[/tex] = 0.5 grams
Mass of Dextrose = 20.0 grams
Mass of [tex]CaCO_3[/tex] = 10. grams
Mass of Agar = 18.0 grams
Volume of solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)
% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution
To calculate the mass of solute, we apply unitary method:
In 1000 mL of solution, the mass of dextrose present is 20.0 grams
So, in 100 mL of solution, the mass of dextrose present will be = [tex]\frac{20.0}{1000}\times 100=2g[/tex]
Calculating the % (m/v) of dextrose, we get:
[tex]\% \text{(m/v) of dextrose}=\frac{\text{Mass of dextrose}}{\text{Volume of solution}}\times 100\\\\\% \text{(m/v) of dextrose}=\frac{2g}{100mL}\times 100=2\%[/tex]
Hence, the percent concentration ( % m/v) of dextrose in the solution is 2 %