Question

Ferrophosphorus (Fe2P) reacts with pyrite (FeS2) producing iron(II) sulfide and a compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.

a. Determine the empirical and molecular formulas of this compound.
b. Empirical Formula: Molecular Formula:
c. Write a balanced chemical equation for this reaction. Do not include phases.

Answer 1

Answer:

The molecular formula of the compound = $P_4S_{10}$

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

Explanation:

Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.

Molar mass of compound = 444.56 g/mol

Number of phosphorus atom = x

Number of sulfur atom = y

Atomic  mass of phosphorus  31 g/mol

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

$=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100$

Phosphorus :

$27.87\%=\frac{x\times 31 g/mol}{444.56 g/mol}\times 100$

x = 4

Sulfur :

$72.13\%=\frac{y\times 32 g/mol}{444.56 g/mol}\times 100$

y = 10

The molecular formula of the compound = $P_4S_{10}$

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

Answer 2

The empirical and molecular formulas of the compound are;

empirical formula = P₂S₅

molecular formula = P₄S₁₀

The balanced chemical reaction is; 4Fe₂P + 18FeS₂ → 26FeS + P₄S₁₀

We are given;

%composition of Phosphorus(P) by mass =  27.87%

%composition of Sulphur(S) by mass = 72.13%

Molar mass of compound = 444.56 g/mol

Now, from tables we have;

Molar mass of P = 31 g/mol

Molar mass of S = 32 g/mol

Thus;

% of element in compound = [(molar mass of element × number of atoms)/(molar mass of compound)] × 100%

For P;

27.87% = ((31 × n_p)/444.56) × 100%

n_p = 4 atoms

For S;

72.13% = ((32 × n_s)/444.56) × 100%

n_s ≈ 10 atoms

Therefore the molecular formula is P₄S₁₀

Now, empirical formula is basically the simplest form of the molecular formula. 4 and 10 both have 2 as a common divisor. Thus, the empirical formula is P₂S₅

Thus, the balanced chemical equation is;

4Fe₂P + 18FeS₂ → 26FeS + P₄S₁₀

Read more at; https://brainly.com/question/13058832