Question

You randomly select 2 marbles from a mug containing 6 blue marbles, 6 red marbles, and 3 white marbles. How many times greater is the probability of selecting 2 red marbles when you replace the first marble before selecting the second marble than when you do not replace the first marble before selecting the second marble? times greater

Answer 1

Answer:

28/25

Step-by-step explanation:

There are a total of 15 marbles, 6 of which are red.

The probability with replacement is:

P = (6/15) (6/15) = 4/25

The probability without replacement is :

P = (6/15) (5/14) = 1/7

The ratio is:

(4/25) / (1/7)

(4/25) × (7/1)

28/25

Answer 2

The probability of selecting 2 red marbles  is greater by

R=28/25

How many times greater is the probability of selecting 2 red marbles?

Question Parameter(s):

You randomly select 2 marbles from a mug containing 6 blue marbles, 6 red marbles, and 3 white marbles.

Generally, the probability   is mathematically given as

Considering replacements

P=(a*b/n)(a*b/n)

P = (6/15) (6/15)

P= 4/25

In conclusion

P' = (6/15) (5/14)

P'= 1/7

Therefore

The ratio

R=(4/25) / (1/7)

R=28/25

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