Which of the following frequencies corresponds to light with the longest wavelength? A) 3.00 times 10^13 s^-1 B) 4.12 times 10^5 s^-1 C) 8.50 times 10^20 s^-1 D) 9.12 times 10^12 s^-1 E) 3.20 times 10^9 s^-1 2. Which of the following are incorrectly paired? A) wavelength - lambda B) frequency - v C) speed of light - c D) hertz - s^-1 E) x-rays - shortest wavelength 3. A line in the spectrum of atomic mercury has a wavelength of 254 nm. When mercury of light at this wavelength, the frequency of this light is A) 8.47 times 10^-16 s^-1 B) 7.82 times 10^-19 s^-1 C) 1.18 times 10^15 s^-1 D) 76.1 s^-1 E) none of these 4. What is the energy of a photon of blue light that has a wavelength of 453 nm? A) 4.53 times 10^-7 J B) 4.39 times 10^-19 J C) 6.62 times 10^14 J D) 9.00 times 10^-32 J E) 2.28 times 10^18 J 5.In Bohr's atomic theory, when an electron moves from one energy level to another distant from the nucleus: A) Energy is emitted. B) Energy is absorbed. C) No change in energy occurs. D) Light is emitted. E) None of these. 6.A given set of p orbitals consists of orbitals. A) 1 B) 2 C) 3 D) 4 E) 5 7.The electron configuration for the barium atom is: A) 1s^22s^22p^63s^23p^64s^23d^10

Respuesta :

Answer:

1) B. 4.12 times 10^5 s^-1

2) B. frequency-v

3) C. 1.18 times 10^15 s^-1

4) B. 4.39 times 10^-19 J

5) B. Energy is absorbed

6) C. 3

7) 1s^2  2s^2  2p^6  3s^2  3p^6  4s^2  3d^10  4p^6  5s^2  4d^10  5p^6     6s^2  

Explanation:

1)

The wavelength is inversely proportional to the frequency. Thus, the smallest frequency shall correspond to the longest wavelength. Thus, the correct answer is B. 4.12 times 10^5 s^-1

2)

B. frequency-v are wrongly paired because frequency is represented by f. Thus, correct pair will be frequency-f.

3)

The relationship between wavelength (λ) and frequency (f) is:

c = fλ

f = c/λ

where, c = speed of light = 3 x 10^8 m/s

f = (3x10^8 m/s) / (254 x 10^-9 m)

f = 1.18 x 10^15 s^-1

Thus, the correct option is C. 1.18 times 10^15 s^-1.

4)

The energy of photon is given as:

E = hc/λ

where, c = speed of light = 3 x 10^8 m/s

            h = Plank's Constant = 6.625 x 10^-34 J.s

E = (6.625 x 10^-34 J.s)(3 x 10^8 m/s) / (453 x 10^-9 m)

E = 4.39 x 10^-19 J

Thus, the correct option is B. 4.39 times 10^-19 J.

5)

Since, the higher energy levels away from nucleus have higher energies. So, in order to move an electron from lower to higher or distant energy level, it must absorb energy from external source. So, the correct option is B. Energy is absorbed.

6)

The P-Sub-level has three orbitals, each having two electrons. Thus, P-Sub-Level accommodates total of 6 electrons. The correct option is C. 3

7)

The electronic configuration of barium atom is:

1s^2  2s^2  2p^6  3s^2  3p^6  4s^2  3d^10  4p^6  5s^2  4d^10  5p^6  6s^2  

Energy is absorbed when an electron moves from a lower to a higher energy level.

The wavelength refers to the distance traveled by a wave in meters. Looking at the options provided in the question, the wavelength is inversely proportional to frequency. The higher the frequency, the shorter the wavelength. From the options provided, 4.12 times 10^5 s^-1 corresponds to the longest wavelength.

Symbols are used to represent the terms that are associated with waves. The symbol v is not used to represent frequency there for the incorrect pair is  frequency - v.

Using the formula;

c = λ f

c = speed of light = 3 × 10^8 m/s

λ  = wavelength =  254  × 10^-9 m

f = ?

f = c/ λ

f =  3 × 10^8 m/s/254  × 10^-9 m

f = 1.18 × 10^15 s^-1

Given that;

E = hc/λ

E = 6.6 × 10^-34 Js ×  3 × 10^8 m/s/453 × 10^-9 m

E = 4.39  × 10^-19 J

According to the Bohr theory, electrons in atoms occupy certain specific energy levels. Energy may be absorbed or emitted when an electron moves from one energy level to another. When an electron moves from one energy level to another distant from the nucleus, energy is absorbed.

The p orbitals are triply degenerate. As such, a given set of p orbitals consists of 3 orbitals. The correct electron configuration for the barium atom is; 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6.

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