Question

A coordinate plane with a line passing through (0, negative 3), (2, 0), and (4, 3).
Which equation represents the graphed function?

–3x + 2 = y
–x + 2 = y
x – 3 = y
2x – 3 = yA coordinate plane with a line passing through (0, negative 3), (2, 0), and (4, 3). Which equation represents the graphed function? –3x + 2 = y –x + 2 = y x – 3 = y 2x – 3 = y

Answer 1

Answer:

$y=\frac{3}{2}x-3$

Step-by-step explanation:

The given line passes through: (0,-3), (2,0), and (4,3).

We first of all find the slope using $m=\frac{y_2-y_1}{x_2-x_1}$

Using $(x_1=0,y_1=-3),and\:(x_2=2,y_2=0)$ we find the slope to be

$m=\frac{0--3}{2-0}=\frac{3}{2}$

The equation is given by $y=mx+c$, where $m=\frac{3}{2}$ is the slope and c=-3 is the y-intercept.

Therefore the equation is $y=\frac{3}{2}x-3$

Answer 2

Answer:

3rd option: 3/2x - 3 = y

Step-by-step explanation:

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