Answer:
1) The smooth trait is dominant.
2) The F1 generation contains the genotype Bb. They will be crossed to form BB: Bb: bb (1: 2:1). The individuals will have the probability of 25% homozygous smooth, 50% heterozygous smooth, 25% wrinkled
B b
B BB Bb
b Bb bb
3) This cross would have shown that there would have been a possibility of 50% homozygous smooth and 50% heterozygous smooth.
B B
B BB BB
b Bb Bb
4) This cross would have resulted in offsprings having a chance of 50% wrinkled and 50% being heterozygous smooth.
B b
b Bb bb
b Bb bb
Explanation: