Respuesta :
Answer:
grams of zinc required = 3.24 g
Particles of zinc required = [tex]2.99\times 10^{22}[/tex]
Explanation:
Given that:-
Mass of hydrogen gas produced = 0.10 g
Calculation of the moles of [tex]H_2[/tex] as:-
Mass = 0.10 g
Molar mass of [tex]H_2[/tex] = 2.016 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{0.10\ g}{2.016\ g/mol}[/tex]
[tex]Moles= 0.0496\ mol[/tex]
According to the reaction shown below:-
[tex]Zn+H_2SO_4\rightarrow ZnSO_4+H_2[/tex]
1 mole of hydrogen gas is produced when 1 mole of zinc reacts
So,
0.0496 mole of hydrogen gas is produced when 0.0496 mole of zinc reacts
Moles of Zinc required = 0.0496 moles
Molar mass of zinc = 65.38 g/mol
mass= Moles*Molar mass = [tex]0.0496\ moles\times 65.38\ g/mol=3.24\ g[/tex]
Also, 1 mole of Zinc contains [tex]6.023\times 10^{23}[/tex] particles
0.0496 mole of Zinc contains [tex]0.0496\times 6.023\times 10^{23}[/tex] particles
Particles of zinc required = [tex]2.99\times 10^{22}[/tex]
