Respuesta :
Answer:
The magnitude of momentum of the airplane is [tex]6.83\times 10^5\ kg-m/s[/tex].
Explanation:
Given that,
Mass of the airplane, m = 3400 kg
Speed of the airplane, v = 450 miles per hour
Since, 1 mile per hour = 0.44704 m/s
v = 201.16 m/s
We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,
[tex]p=mv[/tex]
[tex]p=3400\ kg\times 201.16 \ m/s[/tex]
[tex]p=683944\ kg-m/s[/tex]
or
[tex]p=6.83\times 10^5\ kg-m/s[/tex]
So, the magnitude of momentum of the airplane is [tex]6.83\times 10^5\ kg-m/s[/tex]. Hence, this is the required solution.
Answer:
p=m V
V= 450 mph=0.44*450 meters per second= 198 meters per second
p= 3400*198=673200 kg m/s (in SI units)
Explanation:
momentum is the product of mass and the velocity.
unit conversions are done in SI units
