If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad, at what angle must Ferdinand make each of his jumps?

Respuesta :

Answer:

[tex]36.87^{\circ}[/tex]

Explanation:

v = Velocity of Ferdinand = 5 m/s

[tex]\theta[/tex] = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

[tex]R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}[/tex]

The angle at which Ferdinand make each of his jumps is [tex]36.87^{\circ}[/tex]

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