Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
[tex]W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)[/tex]
The values of the cummulative distribution function of the standard Normal random variable, lets denote it [tex] \phi [/tex] are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
[tex]P(1600< X) = P(\frac{1600-1011}{216} < \frac{X-1011}{216}) = P(2.7269 < W) = 1- \phi(2.7269)\\= 1- 0.9968 = 0.0032[/tex]
Hence, the proportion of scores reported as 1600 is 0.0032.