Respuesta :
Answer:
d = 3.65 g/mL
Explanation:
This problem is solved by using the equation:
d= m/V
But we have to be careful with the number of significant figures and number of decimals to report our result.
There are two steps to calculate the density:
1. We should perform a substraction to determine the mass of potassium chloride.
mass KCl =( Weight cylinder + KCl ) - (Weight empty cylinder)
92.7 g - 5.55 g = 87.15 g = 87.2 ( rounded to 1 decimal place)
The rule for addition and substraction is that we round the result to the number of decimal place with the least number of decimals ( 92.7 has one decimal, 5.55 has two)
2. We can now calculate the density by dividing the mass into the volume, but retaining the number of significant figures to the number with the smallest number of significant figures, the rule for multiplication and division.
d= m/V = 87.2 g / 23.9 mL = 3.648 g/mL
87.2 has three significant figures and so does 23.9, so we have to round to 3 significant figures.
The rule here is that if the left most digital to be dropped is greater o equal to 5, we round to the nearest higher digit, so 8 is greater than 5 and we rounded up 3.648 to 3.65.
The density or the concentration of the potassium chloride solution has been 3.646 g/mL.
The concentration of 1 gram of sample in a mL of solution has been given by density. The density can be expressed as:
[tex]\rm Density=\dfrac{mass}{volume}[/tex]
Computation for Concentration of the solution
The mass of sample dissolved in the solution has been given as the difference in the mass of the sample with the cylinder and the mass of the empty cylinder.
The mass of the sample and cylinder has been [tex]M_T=92.7 \;\rm g[/tex]
The mass of the empty cylinder has been [tex]M_C=5.55 \;\rm g[/tex]
The mass of sample, ([tex]M_S[/tex]) has been given as:
[tex]M_S=M_T-M_C[/tex]
Substituting the values in the equation:
[tex]M_S=92.7\;-\;5.55\\M_S=87.15\;\rm g[/tex]
The mass of the sample has been 87.15 g.
The volume of the final solution prepared has been 23.9 mL.
Substituting the values for the density of the sample:
[tex]\rm Density=\dfrac{87.15}{23.9}\;g/mL\\Density=3.646\;g/mL[/tex]
The density or the concentration of the potassium chloride solution has been 3.646 g/mL.
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