Question

Graph the equation by plotting three
points. If all three are correct, the line
will appear.
2y = -3x+2​

Answer 1

Answer:

The three points $\:\left(\frac{2}{3},\:0\right)$, $\:\left({0},\:1\right)$, and $(2, -2)$ are plotted to make the graph of the line $2y = -3x+2$, as shown in attached graph figure.

Step-by-step explanation:

As

$2y = -3x+2$

$\mathbf{y=mx+b}\:\mathrm{is\:the\:slope\:intercept\:form\:of\:a\:line\:where}$ $\mathbf{m}\:\mathrm{is\:the\:slope\:and}\:\mathbf{b}\:\mathrm{is\:the}\:\mathbf{y}\:\mathrm{intercept}$.

So,

$\mathrm{For\:a\:line\:in\:the\:form\:of\:}\mathbf{y=mx+b}\mathrm{,\:the\:slope\:is}\:\mathbf{m}\:\mathrm{and}\:\mathbf{y}\:\mathrm{intercept\:is}\:\mathbf{b}$

$y=-\frac{3}{2}x+1$

$m=-\frac{3}{2}$ is the slope.

Putting y = 0 in $y=-\frac{3}{2}x+1$ will bring x-intercept.

So,

$\mathrm{X\:Intercepts}:\:\left(\frac{2}{3},\:0\right)$

Similarly,

Putting x = 0 in $y=-\frac{3}{2}x+1$ will bring y-intercept.

So,

$\mathrm{Y\:Intercepts}:\:\left(0,\:1\right)$

Also, putting x = 2 in $y=-\frac{3}{2}x+1$ will being y = -2

So, the three points $\:\left(\frac{2}{3},\:0\right)$, $\:\left({0},\:1\right)$, and $(2, -2)$ are being plotted to make the graph of the line $2y = -3x+2$, as shown in attached graph figure.

The graph is attached below.

Keywords: graph, point, equation

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