Question

In a Little League baseball game, the 145 g ball enters the strike zone with a speed of 15.0 m/s . The batter hits the ball, and it leaves his bat with a speed of 20.0 m/s in exactly the opposite direction?

Answer 1

Answer:

Explanation:

Given

mass of ball $m=145\ gm$

initial speed $u=15\ m/s$

Final speed $v=20\ m/s$

Impulse Delivered by bat to the ball

$J=change in\ momentum\ of\ ball$

$\Delta P=change\ in\ momentum$

$\Delta P=m(v-u)$

$\Delta P=0.145(-20-15)$

$\Delta P=-5.075\ N.s$

if ball makes a contact for t sec

then average force applied is

$F_{avg}=\frac{\Delta P}{t}$

Answer 2

Answer:

5.075 N s

Explanation:

mass, m = 145 g = 0.145 kg

initial velocity, u = 15 m/s

final velocity, v = - 20 m/s

Impulse = change in momentum

Impulse = m ( v - u)

Impulse = 0.145 ( 20 + 15)

Impulse = 5.075 N s

Thus, the impulse is 5.075 N s .