Answer:
[tex]v_2 \approx 1.12246\ m.s^{-1}[/tex]
[tex]v_{10}\approx 1.4678\ m.s^{-1}[/tex]
[tex]v_{100}\approx 1.4678\ m.s^{-1}[/tex]
Step-by-step explanation:
Mass of particles that a river can transport, [tex]m\propto\ v^6[/tex]
where:
v = velocity of river flow
When [tex]v=1\ m.s[/tex]
then the mass transported, [tex]m \propto 1^6[/tex]
When mass is twice:
[tex]v=\sqrt[6]{2}[/tex]
[tex]v_2 \approx 1.12246\ m.s^{-1}[/tex]
When mass is 10 times:
[tex]v=\sqrt[6]{10}[/tex]
[tex]v_{10}\approx 1.4678\ m.s^{-1}[/tex]
When mass is 100 times:
[tex]v=\sqrt[6]{100}[/tex]
[tex]v_{100}\approx 1.4678\ m.s^{-1}[/tex]