Answer:50 N
Explanation:
Given
Friction force [tex]f_r=0.2\ N[/tex]
coefficient of kinetic friction [tex]\mu_k=0.04[/tex]
and Friction force for a moving object is given by the product of coefficient of kinetic friction and Normal reaction
[tex]f_r=\mu _k\times N[/tex]
[tex]f_r=0.04\times N[/tex]
[tex]N=\frac{0.2}{0.04}=50\ N[/tex]
Answer:
5 N
Explanation:
Friction force, f = 0.2 N
coefficient of friction, μ = 0.04
According to the laws of friction
Friction force = μ x Normal reaction
0.2 = 0.04 x N
N = 5
Thus, the normal force is 5 N.