Answer:
12824.74 N
Explanation:
mass of bullet, m = 21 g = 0.021 kg
distance, s = 114 cm = 1.14 m
final velocity, v = 1180 m/s
initial velocity, u = 0
Let F be the force .
By use of work energy theorem
Work done = change in kinetic energy
F x s = 1/2 m v² - 1/2 mu²
F x 1.14 = 0.5 x 0.021 x 1180 x 1180
F = 12824.74 N
A 21 g bullet is accelerated with a force of 2.5 × 10³ N in a rifle barrel 114 cm long to a speed of 1180 m/s.
A 21 g (m) bullet is accelerated from rest (u = 0 m/s) to 1180 m/s (v). We can calculate the change in the kinetic energy (ΔK) using the following expression.
[tex]\Delta K = K_f - K_i = 1/2 \times m \times v^{2} - 1/2 \times m \times u^{2} = 1/2 \times m \times v^{2} = 1/2 \times 0.021kg \times (1180m/s)^{2} = 2.9 \times 10^{3} J[/tex]
The bullet is accelerated in a 114 cm (d) riffle barrel.
According to the work-energy theorem, the work done is equal to the change in the kinetic energy.
[tex]2.9 \times 10^{3} J = W = F \times d\\\\F = \frac{2.9 \times 10^{3} J}{1.14m} = 2.5 \times 10^{3} N[/tex]
A 21 g bullet is accelerated with a force of 2.5 × 10³ N in a rifle barrel 114 cm long to a speed of 1180 m/s.
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