Question

Some of the fastest dragsters (called "top fuel) do not race for more than 300-400m for safety reasons. Consider such a dragster in this problem, starting a race at rest. After the light turns green, the dragster completes a 400 m race in a time t = 8.6 5. Otheexpertta.com A 50% Part (a) How many times larger is the dragster's acceleration during this period than the acceleration due to gravity? alg Grade Summary Deductions Potential 16096 sino cos fano cotano asin) acos atan acotan) sinh cosho tanho cotanho Deprees Radians Submissions Attempts remaining: 5 ( per attempt) detailed view Sabrit Feedback: deduction per feedback Hinta o deduction per hist. Hints remaining 2 H A 50% Part (b) If the dragster could continue with this average acceleration, what would its speed be, in miles per hour, after it has travelled a total distance of 1.6 km (-1.0 mile)? All LLC

Answer 1

Answer:

1.10261 times g

416.17506 mph

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow 400=0\times 8.6+\frac{1}{2}\times a\times 8.6^2\\\Rightarrow a=\frac{400\times 2}{8.6^2}\\\Rightarrow a=10.81665\ m/s^2$

Dividing by g

$\dfrac{a}{g}=\dfrac{10.81665}{9.81}\\\Rightarrow \dfrac{a}{g}=1.10261\\\Rightarrow a=1.10261g$

The acceleration is 1.10261 times g

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 10.81665\times 1.6\times 10^3+0^2}\\\Rightarrow v=186.04644\ m/s$

In mph

$186.04644\times \dfrac{3600}{1609.34}=416.17506\ mph$

The speed of the dragster is 416.17506 mph

Answer 2

(a) The acceleration will be "1.10261 g".

(b) The speed of dragster will be "416.17506 mph".

According to the question,

• Displacement, s = 400 m
• Time taken, t = 8.6 seconds
• Acceleration due to gravity, g = 9.81 m/s²

(a)

We know,

→ $s = ut+\frac{1}{2}at^2$

By putting the values,

$400=0\times 8.6+\frac{1}{2}\times a\times 8.6^2$

    $a = \frac{400\times 2}{8.6^2}$

       $= 10.81665 \ m/s^2$

By dividing "g",

→ $\frac{a}{g} = \frac{10.81665}{9.81}$

      $= 1.10261$

   $a = 1.10261 \ g$

(b)

We know,

→ $v^2-u^2 =2as$

or,

→ $v = \sqrt{2as+u^2}$

By putting the values,

     $= \sqrt{2\times 10.81665\times 1.6\times 10^3+0^2}$

     $= 186.04644 \ m/s$

By converting it into "mph", we get

     $= 186.04644\times \frac{3600}{1609.34}$

     $= 416.17506 \ mph$

Thus the above answer is right.              

Learn more about acceleration here:

https://brainly.com/question/14447109