Answer:
The strength of the electric field on the point charge at this distance is 4000 N.
Explanation:
The electric field strength is determined using the formula[tex]E=\frac{kQ}{d^{2} }[/tex]
Thus, field strength is directly proportional to the charge of the charge and inversely proportional to the square of the distance between them. In the above equation, Q is the charge and d is the distance, k is the constant 9×[tex]10^{9}[/tex]
So, the electric field strength will be
[tex]E=\frac{9*10^{9} *4*10^{-6} }{9}=4*10^{3} =4000 N[/tex]
So the electric field strength is 4000 N.