Respuesta :
Answer:
The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,
Explanation:
To answer this problem we need to keep in mind the definition of pH:
- pH = -log [H⁺]
So now we calculate [H⁺] using a pH value of 5.2 and of 5.6:
- 5.2 = -log [H⁺]
-5.2 = log [H⁺]
[tex]10^{-5.2}[/tex] = [H⁺]
6.31 x 10⁻⁶ M = [H⁺]
- 5.6 = -log [H⁺]
-5.6 = log [H⁺]
[tex]10^{-5.6}[/tex] = [H⁺]
2.51 x 10⁻⁶ M = [H⁺]
when we calculate [H⁺] using a pH value of 5.2 and of 5.6:
- Then the 5.2 = -log [H⁺]
- Then -5.2 = log [H⁺]
- After that = [H⁺]
- Now 6.31 x 10⁻⁶ M = [H⁺]
- Then 5.6 = -log [H⁺]
- Then -5.6 = log [H⁺]
- After that = [H⁺]
- Now 2.51 x 10⁻⁶ M = [H⁺]
- Answer: When The range of [H⁺] is from 2.51 x 10⁻⁶ M to 6.31 x 10⁻⁶ M,
- When To answer this problem we need to keep in mind the definition of pH:
- So that pH = -log [H⁺]
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