Answer:
0.133kg.m/s
Explanation:
Using equation of motion
v² = u² + 2as where v is the final velocity in m/s, a = g = 9.81 m/s² and s is the height and u = 0
v² = 2×9.81×1.44m
v = √(2×9..81×1.44) = 5.312 m/s taking downward movement as negative
v = -5.312 m/s
the marble bounces straight upward to a height of 0.64 m
again
v² = u² + 2as where final velocity = 0
-u² = (2 × -9.81 × 0.64)
u = √12.5568 = 3.544m/s
impulse = m × Δv = 0.15 × ( 3.544 --5.312 ) = 0.15 × (3.544+5.312) = 0.133kg.m/s
