Question

A stone is thrown vertically upward with an initial speed of 19.3 m/s. Neglect air resistance. The speed of the stone when it is 5.81 m higher is:

Answer 1

U=19.3
A=-9.81
S=5.81
V=?
V^2=u^2+2as
V^2=372.49+(2*-9.81*5.81)
V=final speed at 5.81m=16.1 ms^-1