Respuesta :
Answer:
[tex]1\times 10^4\ times[/tex]
Step-by-step explanation:
Given:
Width of average grain of salt is, [tex]w=0.0003\ m[/tex]
Width of Rhinovirus is, [tex]W=0.00000003\ m[/tex]
Now, expressing each width in scientific notation form, we get:
[tex]w=0.0003\ m = 3\times 10^{-4}\ m\\\\W=0.00000003\ m = 3\times 10^{-8}\ m[/tex]
Now, in order to get how many times 'W' is wider than 'w', we divide the two widths. This gives,
[tex]\frac{W}{w}=\frac{3\times 10^{-4}\ m}{3\times 10^{-8}\ m}\\\\\frac{W}{w}=1\times 10^{-4-(-8)}=1\times 10^{-4+8}=1\times 10^4\\\\\therefore W=1\times 10^4\times w[/tex]
Therefore, the grain of salt is [tex]1\times 10^4\ times[/tex] wider than Rhinovirus.
To solve such problems we must know about ratio.
Ratio
A ratio shows us the number of times a number contains another number.
The number of times a grain of salt is wider than Rhinovirus is 10,000 times.
Given to us
- The average grain of salt is 0.0003 meters wide.
- Rhinovirus, which causes the common cold, is 0.00000003 meters wide.
Solution
Number of times a grain of salt is wider than Rhinovirus
[tex]=\dfrac{width\ of \ average\ grain\ of\ salt}{Width\ of\ Rhinovirus}[/tex]
[tex]=\dfrac{0.0003}{0.00000003}\\\\ =1\times 10^4[/tex]
Hence, the number of times a grain of salt is wider than Rhinovirus is 10,000 times.
Learn more about Ratio:
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