Question

Suppose you are fishing and you expect to get a fish once every 30 minutes. Compute the probability that you will have to wait between 2 to 4 hours before you catch 4 fish.

Answer 1

Answer:

Step-by-step explanation:

probability that you will have to wait between 2 to 4 hours before you catch 4 fish =P(4 or more fish in 4 hours)-P(4 or more fish in 2 hours) =P(1-at most 3 fish in 4 hours)-P(1-at most 3 fish in 2 hours)

$\sum\limits^3 {e^{-8}8^x/x!}\sum\limits^3{e^{-4}4^x/x!}\\\\=(1-x=0)-(1-x=0)\\\\=(1-0.042380)-(1-0.433470)=0.391090$