Question

Write the ionization equations for the three ionizations of phosphoric acid. Calculate the pKa for each reaction.

Answer 1

Answer:H3PO4=H^+ + H2PO4^- pka=2.125. H2PO4^- =H^+ + HPO4^-2 pka=7.208. HPO4^-2= H^+ + PO4^-3 pka=12.444

Explanation:H3PO4 is a polyprotic acid thus has 3 protons to donate. To calculate the pka we have. Pka=-logka

The ka for each are as follows respectively. 7.5×10^-3. 6.2×10^-8.

3.6×10^-13