Question

A 95% confidence is given by (15,20) . The interval is based on a sample of size n=25 .

If we want to reduce the margin of error by half, we need to:

a. double the sample size.

b. quadruple the sample size.

Answer 1

Answer:

b. quadruple the sample size.

Step-by-step explanation:

Given that a 95% confidence is given by (15,20) .

this implies that mean = average of lower and higher bounds of confidence interval = $\frac{15+20}{2} =17.5$

Margin of error = Upper bound - Mean = $20-17.5 = 2.5$

Confidence level = 95%

Critical value = 1.96

Std  error = $\frac{2.5}{1.96} =1.27551$

Std devition = Std error * sqrt n = 6.3775

If we want to reduce margin of error by half we must get margin of error as 1.25

For that std error for same critical value = 0.63775

Std deviation did not change

So sample size only changed which implies that sample size is 4 times the original

b. quadruple the sample size.