Nondisjunction during meiosis results in an abnormal number of chromosomes in one or more gametes. In some cases of nondisjunction, a single chromosome fails to separate. In others, none of the chromosomes separate. Suppose an egg is produced in which none of the chromosomes separate during meiosis II. What is the chromosome number of the zygote that results if this egg is fertilized by a normal sperm?

If none of the chromosomes separate during meiosis, the resulting gametes will either lack chromosome or have diploid number (2n) of chromosome instead of a haploid number.

If an egg without chromosome (o) fertilizes a normal sperm (n), the resulting zygote will have haploid number (n) of chromosome.

If an egg with diploid number of chromosome (2n) fertilizes a normal sperm (n), the resulting zygote will be a triploid with 3n number of chromosome.

kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-12-16T09:54:03+01:00

Non-disjunction during meiosis is defined as the copying of the abnormal number of chromosomes in the gametes. The single chromosome fails to replicate and separate during the division.

The conditions for non-disjunction can be explained as:

1. If an egg having no chromosome fuses with the sperm cell having a haploid number of chromosomes, then the resultant daughter cell will have the haploid number of chromosomes.

2. If the egg cell consists of a 2n number of chromosomes (diploid), when fuses with the sperm cell (haploid), it will give rise to the daughter cell having triploid or 3n number of chromosomes.

Thus, the failure of the separation of chromosomes during meiosis can result in aneuploidy.

To know more about non-disjunction, refer to the following link;

https://brainly.com/question/22271293