Question

Help plz, need it fast, will brainliest!!! A square piece of paper has an area of LaTeX: x^2x 2 square units. A rectangular strip with a width of 2 units and a length of LaTeX: xx units is cut off of the square piece of paper. The remaining piece of paper has an area of 120 square units. Which equation can be used to solve for LaTeX: xx, the side length of the original square? Group of answer choices

Answer 1

Question:

A square piece of paper has an area of x^2 square units. A rectangular strip with a width of 2 units and a length of x units is cut off of the square piece of paper. The remaining piece of paper has an area of 120 square units.

Which equation can be used to solve for x, the side length of the original square?

Answer:

$x^2-2x-120=0$ is the equation used to solve for side length of original square

Solution:

Let "x" be the length of side of original square paper

Let $A_1$ be the area of original square paper

Given that, square piece of paper has an area of $x^2$ square units

$A_1 = x^2$

A rectangular strip with a width of 2 units and a length of x units is cut off of the square piece of paper.

Let us find the area of rectangular strip

Let $A_2$ be the area of rectangular strip

$Area = length \times width\\\\A_2 = x \times 2 = 2x$

The area of the remaining piece of paper is equal to:

Let $A_3$ be the area of remaining piece of paper

Area of remaining piece of paper = Area of original square - Area of rectangular strip

$A_3 = A_1 -A_2\\\\A_3 = x^2-2x$

The remaining piece of paper has an area of 120 square units

Therefore,

$120 = x^2-2x\\\\x^2-2x-120=0$

Thus the above equation is used to solve for side length of original square

Answer 2

Answer:

the answer is x² - 2x - 120 = 0

Step-by-step explanation: