Answer
Speed of 320 gram cart will be 0.377 m /sec
Explanation:
We have given mass of the air track [tex]m_1=320gram=0.32kg[/tex]
Velocity of the air track [tex]v_1=1.25m/sec[/tex]
Mass of the cart [tex]m_2=270gram=0.270kg[/tex]
Cart is at stationary so velocity of cart [tex]v_2=0m/sec[/tex]
Now according to conservation of momentum
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
[tex]0.32\times 1.25+0.270\times 0=(0.320+0.270)v[/tex]
[tex]v=0.677m/sec[/tex]
