Answer:
The answer to your question is 18.26 g of HNO₃
Explanation:
Data
mass of HNO₃ = ?
mass of NO₂ = 20 g
Balanced equation
3NO₂ + H₂O ⇒ 2HNO₃ + NO
Checked that the equation is balanced
Reactants Elements Products
3 N 3
7 O 7
2 H 2
This equation is balanced
- Calculate the molecular mass of
- HNO₃ = (1 x 1) + (14 x 1) + (16 x 3) =63 g
- NO₂ = (1 x 14) + (16 x 2) = 46 g
- Use proportions to find the answer
3(46) g of NO₂ --------------- 2(63) g of HNO₃
20 g of NO₂ -------------- x
x = (20 x 126) / 138
x = 2520 / 138
x = 18.26 g of HNO₃
Answer:
We'll have 18.27 grams of HNO3
Explanation:
Step 1: Data given
Mass of NO2 = 20.0 grams
Molar mass of NO2 = 46.01 g/mol
Step 2: The balanced equation
3NO2 + H2O → 2HNO3 + NO
Step 3: Calculate moles NO2
Moles NO2 = mass NO / molar mass NO
Moles NO2 = 20.0 grams / 46.01 g/mol
Moles NO2 = 0.435 moles
Step 4: Calculate moles HNO3
For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO
For 0.435 moles NO2 we'll have 2/3 * 0.435 = 0.290 moles HNO3
Step 5: Calculate mass of HNO3
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.290 moles * 63.01 g/mol
Mass HNO3 = 18.27 grams
We'll have 18.27 grams of HNO3
