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Triangle Classification Theorems
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Creating an Acute Triangle
The sides of a triangle have length x x + 4, and 20. If the length of the longest side is 20, which value of x would
make the triangle acute?
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Answer:

The value of x for the triangle to be acute triangle is 0 < x < 12.

Step-by-step explanation:

If we consider that a right triangle has side lengths x, x + 4, and 20 having 20 as the hypotenuse.

So, x² + (x + 4)² = 20²

Now, the condition for the triangle with sides x, (x + 1), and 20 to be acute triangle is x² + (x + 4)² < 20²

⇒ x² + x² + 8x + 16  < 400

⇒ 2x² + 8x - 384 < 0

⇒ x² + 4x - 192 < 0

⇒ x² + 16x - 12x - 192 < 0

(x + 16)(x - 12) < 0

Therefore, either (x + 16) > 0 and (x - 12) < 0

⇒ x > - 16 and x < 12

Or, (x + 16) < 0 and (x - 12) > 0

⇒ x < - 16 and x > 12, which is impossible.

Therefore, the value of x for the triangle to be an acute triangle is 0 < x < 12, as x can not be ≤ 0. (Answer)

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