The horizontal surface on which the block slides is frictionless. If F = 20 N and M = 5.0 kg, what is the magnitude of the resulting acceleration of the block?

Respuesta :

Answer:

[tex]a=4m/s^2[/tex]

Explanation:

Using Newton's second law:

[tex]F=ma[/tex]

Where [tex]F[/tex] is the force applied on the object, [tex]m[/tex] is the mass of the object, and [tex]a[/tex] is the acceleration.

In this case we need the acceleration, so we clear for [tex]a[/tex]:

[tex]a=\frac{F}{m}[/tex]

we know that the force is: [tex]F=20N[/tex], and the mass: [tex]m=5kg[/tex]

so the acceleration:

[tex]a=\frac{20N}{5kg}[/tex]

[tex]a=4m/s^2[/tex]

the acceleration of the block is: [tex]a=4m/s^2[/tex]

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