Question

500 J of work is done on a system in a process that decreases the thermal energy of the system by 100 J . How much heat energy is transfered to or from the system?

Answer 1

Answer:

So 600 J energy is transferred from the system

Explanation:

We have given 500 J work is done on the system

So $W=500J$

In thus process thermal energy is decreases by 100 J

So $\Delta E=-100J$

According to thermodynamics

$\Delta E=Q+W$

So $Q=\Delta E-W=-100-500=-600J$  

Answer 2

The amount of heat energy is transferred  from the system is of -600 J.

Given data:

The work done on the system is, W = - 500 J. (negative sign shows that work is done on the system)

The decrease in thermal energy (internal energy) is, U = -100 J. (negative sign shows the decrement)

Use first law of thermodynamics, which says that the total heat supplied to system is equal to the sum of work done and thermal energy. Therefore,

Q = W + U

Q = - 500 + (-100)

Q = - 600 J.

Negative sign shows that heat energy is transferred from the system.

Thus, the amount of heat energy is transferred  from the system is of -600 J.

Learn more about the first law of thermodynamics here:

https://brainly.com/question/3808473