Question

A football punter accelerates a 0.59 kg football from rest to a speed of 6.6 m/s in 0.34 s, what constant force does the punter exert on the ball?

Answer 1

Answer:

F= 11.45N

Explanation:

Using the formula;  F=ma

Where, $a=\frac{v-u}{t}$

$F =m*\frac{v-u}{t}$

m=0.59kg,    v=6.6m/s,   t=034s     u=0 (the body starts from rest

We will input these values into equation 1 to get the force magnitude.

$F =0.59*\frac{6.6-0}{0.34}$

F= 11.45N