Answer:
two imaginary solutions. No real solutions
Step-by-step explanation:
Use the discriminant to find the number of real solutions of the equation
3x^2 – 5x + 4 = 0
To find discriminant we use formula
D= b^2 - 4ac
D =0 , 1 real solution
D>0, 2 real solutions
D<0, 2 imaginary solutions
3x^2 – 5x + 4 = 0
from the given equation, a= 3 , b= -5 and c= 4
D= b^2 - 4ac= (-5)^2 - 4(3)(4)= 25- 48= -23
D is negative that means D<0
So , two imaginary solutions