4) You have a spring-loaded air rifle. When it is loaded, the spring is
compressed 0.3 m and has a spring constant of 150 N/m. In joules, how
much elastic potential energy is stored in the spring?

Respuesta :

The potential energy of the spring is 6.75 J

Explanation:

The elastic potential energy stored in a spring is given by the equation:

[tex]E=\frac{1}{2}kx^2[/tex]

where

k is the spring constant

x is the compression/stretching of the string

For the spring in this problem, we have:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting, we find

[tex]E=\frac{1}{2}(150)(0.3)^2=6.75 J[/tex]

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