The potential energy of the spring is 6.75 J
Explanation:
The elastic potential energy stored in a spring is given by the equation:
[tex]E=\frac{1}{2}kx^2[/tex]
where
k is the spring constant
x is the compression/stretching of the string
For the spring in this problem, we have:
k = 150 N/m is the spring constant
x = 0.3 m is the compression
Substituting, we find
[tex]E=\frac{1}{2}(150)(0.3)^2=6.75 J[/tex]
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