Answer:
The solution of this system is
(4). (6.0,5.4)
Step-by-step explanation:
First we have to find the equation of the line represented in the table; for that we have to find it's slope [tex]m[/tex] and it's y-intercept [tex]b[/tex] and then write it in the following form:
[tex]y=mx+b[/tex]
The slope [tex]m[/tex] of the line we get from first two points:
[tex]m=\frac{3.8-3.2}{(-2)-(-5)} =0.2[/tex]
thus we have
[tex]y=0.2x+b[/tex]
we find [tex]b[/tex] by putting the point [tex](2,4.6)[/tex] into the function:
[tex]4.6=0.2(2)+b[/tex]
[tex]b=4.6-0.4=4.2[/tex]
Thus we have
[tex]y=0.2x+4.2[/tex]
Now we have to find where this line intersects with [tex]4y+2x=33.6[/tex]; to do this we just substitute [tex]y[/tex] with [tex]y=0.2x+4.2[/tex]:
[tex]4(0.2x+4.2)+2x=33.6[/tex]
[tex]0.8x+16.8+2x=33.6[/tex]
[tex]\boxed{x=6 }[/tex]
We have the x-coordinate of the intersection.
We find the y-coordinate by substituting [tex]x=6[/tex] into [tex]y=0.2x+4.2[/tex]:
[tex]y=0.2(6)+4.2=5.4[/tex]
[tex]\boxed{y=5.4}[/tex]
Thus the solution to the system is
[tex]\boxed{(x,y)=(6, 5.4)}[/tex]
which is option 4.