Answer: A (10,-6)
Step-by-step explanation:
step 1:- The equation of the circle is given center and radius is
[tex](x-h)^{2} +(y-k)^{2} = r^{2}[/tex]
Step 2:-
A circle has its center at (6,-3) and point on the circle is (3,1),Now
we have find radius from center to the given point on the circle
The distance of two points are
[tex]\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1} )^2 }[/tex]
[tex]\sqrt{(1-(-3))^2+(3-6)^2}[/tex]
[tex]\sqrt{25}[/tex]
[tex]r=5[/tex]
step 3:-
The equation of the circle having center and radius is
[tex](x-6)^{2}+(y+3)^2=5^{2}[/tex]
verification:
This circle is passing through the point (10,-6)
[tex](10-6)^{2}+(-6+3)^2=25[/tex]
[tex]25 =25[/tex]
There fore the another point that lies on the circle is (10,-6).