Answer:
Step-by-step explanation:
Given that the probability that an American company will open a location in Shanghai, China is 0.7.
The probability that it will open a location in Beijing, China is 0.4.
The probability that it will open a location in either Shanghai or Beijing or both is 0.8.
the probability that the company will open a location in:
(a) both Shanghai and Beijing :
[tex]0.7+0.4-P(both)=0.8[/tex]
P(both) = 0.3
(using addition theory of probability for union of sets)
(b) neither Shanghai nor Beijing
= 1- P(AUB)
[tex]=1-0.8 = 0.2[/tex]
(c) Beijing but not in Shanghai?
P(Beiging)_P(both) = [tex]0.4-0.3=0.1[/tex]
(d) Shanghai given that it opens a location in Beijing
=P(Both)/P(Beijing) = [tex]\frac{0.3}{0.4} =0.75[/tex]