Answer:
Ethan's cylinder has a larger total surface area
Step-by-step explanation:
we know that
The surface area of a cylinder is equal to
[tex]SA=2\pi r^{2}+2\pi rh[/tex]
step 1
Find the surface area of Tommy's cylinder
we have
[tex]r=6.2/2=3.1\ in[/tex] ----> the radius is half the diameter
[tex]h=8.8\ in[/tex]
substitute in the formula
[tex]SA=2\pi (3.1)^{2}+2\pi (3.1)(8.8)[/tex]
[tex]SA=19.22\pi+54.56\pi[/tex]
[tex]SA=73.78\pi\ in^2[/tex]
step 2
Find the surface area of Ethan's cylinder
we have
[tex]r=8.8/2=4.4\ in[/tex] ----> the radius is half the diameter
[tex]h=6.2\ in[/tex]
substitute in the formula
[tex]SA=2\pi (4.4)^{2}+2\pi (4.4)(6.2)[/tex]
[tex]SA=38.72\pi+54.56\pi[/tex]
[tex]SA=93.28\pi\ in^2[/tex]
Compare
[tex]93.28\pi\ in^2 > 73.78\pi\ in^2[/tex]
therefore
Ethan's cylinder has a larger total surface area