Question

Evaluate the following expression using the values given:

Find −a2 − 3b3 + c2 + 2b3 − c2 if a = 3, b = 2, and c = −3.

Answer 1

I got 12.
The two c2's cancel each other out.
-3b3+2b3 = -b3.
-a2 remains the same.
Therefore, we get -2a-3b.
That would be -2(3)-3(2)=-6-6 = -12.
Hope this helps!