Question

What is the product of (2p + 7)(3p2 + 4p – 3)?

6p3 + 29p2 – 34p + 21
6p3 + 29p2 – 22p + 21
6p3 + 29p2 + 22p – 21
6p3 + 29p2 + 34p – 21

Answer 1

C. 6p3 + 29p2 + 22p - 21
Hope this helps!!!

Answer 2

Answer: $6p^3 + 29p^2 + 22p – 21$

Step-by-step explanation:

The given expression : $(2p + 7)(3p^2 + 4p - 3)$

To find the product, we need to use the distributive property.

The distributive property is given by :-

$a(b+c)=ab+ac$

Then , the product will become:

$(2p + 7)3p^2 + (2p + 7)4p - (2p + 7)3\\\\=\\\\=(2p*3p^2 + 7*3p^2)+(2p*4p + 7*4p)-(2p*3 + 7*3)\\\\=6p^{2+1}+21p^2+8p^{1+1}+28p-6p-21........\text{Since }a^ma^n=a^{m+n}\\\\=6p^3+21p^2+8p^2+22p-21\\\\=6p^3 + 29p^2 + 22p - 21$