Answer:
The 32nd term of Arithmetic sequence is -174
Step-by-step explanation:
Given: [tex]a_1=12, a_{13}=-60[/tex]
We are given two term of the Arithmetic sequence.
Formula:
[tex]a_n=a+(n-1)d[/tex]
For [tex]a_1=12[/tex]
[tex]a=12[/tex]
For [tex]a_{13}=-60[/tex]
[tex]a+12d=-60[/tex]
Using two equation solve for a and d
[tex]12+12d=-60[/tex]
[tex]1+d=-5[/tex]
[tex]d=-6[/tex]
We need to find 32nd term
[tex]a_{32}=a+31d[/tex]
[tex]a_{32}=12+31(-6)[/tex]
[tex]a_{32}=12-186[/tex]
[tex]a_{32}=-174[/tex]
Hence, The 32nd term of Arithmetic sequence is -174
Answer:
- 174
Step-by-step explanation:
The nth term of an arithmetic sequence is given as
Tn = a + (n - 1)d
where Tn is the nth term
a is the first term , n is the number of term and d is the common difference. As such,
a13 = a + (13 - 1)d
= a + 12d
Given that a1 = 12 and a13 = -60
-60 = 12 + 12d
12d = -72
d = -6
Hence a32 which is the 32nd term
= 12 + (32 - 1)-6
= 12 + (-186)
= - 174
