A line passes through the point (–2, 4), and its y-intercept is (0, –6). What is the equation of the line that is perpendicular to the first line and passes through the point (5, –4)?
a. y=1/3x-3
b. y=5x-3
c.y=1/5x-5
y=5/3x-2
y= mx +b the first line: sustitute: 4=m(-2)+b remplace intercept in y: 4=-2m-6 -2m=(4+6)/-2 m=-5 The first equation is y=-5x-6 For the perpendicular the slope is 1/5 so y-y1=m(x-x1) use the second coordenates y+4= 1/5(x-5) y=(1/5)x-1-4 y=(1/5)x-5 That's the answer: Letter C
little late for me now but for future reference those equations are y=mx+b form X is rise/run and B if you go up or down, then its just a matter of graphing your lines to determine the point of intersection. you might've gotten youre answer, maybe not but now you can find it in less time
