Respuesta :
The little lump of platinum that you dropped into the graduated cylinder has
(5.3 - 5.0) = 0.3 mL = 0.3 cm³ of volume.
That's nothing but a metal shaving, a little sliver, maybe like
a 1/4-inch piece cut out of a metal paper-clip. I'm surprised
that you can read the graduated cylinder that precisely.
Its mass is
(0.3 cm³) x (21 gm/cm³) = 6.3 grams = 0.0063 kg .
(5.3 - 5.0) = 0.3 mL = 0.3 cm³ of volume.
That's nothing but a metal shaving, a little sliver, maybe like
a 1/4-inch piece cut out of a metal paper-clip. I'm surprised
that you can read the graduated cylinder that precisely.
Its mass is
(0.3 cm³) x (21 gm/cm³) = 6.3 grams = 0.0063 kg .
Answer:
The mass of the ring is 6.3 kg.
Explanation:
It is given that,
Density of platinum, [tex]d=21\ g/cm^3[/tex]
A platinum ring is placed in a graduated cylinder that contains water. the water level rises from 5.0 ml to 5.3 ml when the ring is added. the volume of the ring is, (5.3 - 5) mL = 0.3 mL
Volume of the ring, [tex]V=0.3\ cm^3[/tex]
We need to find the mass of the ring. The density of any substance is given by :
[tex]d=\dfrac{m}{V}[/tex]
[tex]m=d\times V[/tex]
[tex]m=21\ g/cm^3\times 0.3\ cm^3[/tex]
m = 6.3 kg
So, the mass of the ring is 6.3 kg. Hence, this is the required solution.