Question

One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hypotenuse?

Answer 1

since it is isosceles right triangle, both legs = 5 inches.

using pythagoras theorem,


hypotenuse^2 = 5^2 +5^2 = 25+25 = 50
taking square root on both sides,
hypotenuse = sqrt 50  = 5 sqrt 2 or 7.071

rounded to nearest tenth,
length of hypotenuse is 7.1 inches.

Answer 2

The answer is  7.07 inch

What is Pythagoras theorem?

The theorem attributed to Pythagoras that the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides.

From the given question , it is a isosceles right triangle

The base and perpendicular is given  5 inc.

By using Pythagoras theorem

$h^{2} = p^{2} + b^{2} \\h^{2} = 5^{2} + 5^{2} \\h^{2} = 25 +25\\h^{2} = 50\\h = \sqrt{50} \\h = 7.07 inch$

Therefore , the approximate length of the hypotenuse is 7.07 inch

learn more about Pythagoras theorem here:

https://brainly.com/question/343682

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