Question

the vertex of the graph of y=(x-1)^2-5 is

Answer 1

for y  = (x-h)^2 + k
the vertex is h,k

comparing
y=(x-1)^2-5  with  y  = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5  is  (1,-5)

Answer 2

Answer:

(1,-5)

Step-by-step explanation: