Question

The volume, in liters, of 835 g SO3 at STP. Show your work.

Answer 1

Answer:

233.856 L

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

So first of all you should know the amount of moles that represents 835 g of SO₃. For that, you know that:

• S: 32 g/mole
• O: 16 g/mol

So: SO₃= 32 g/mol + 3*16 g/mol= 80 g/mol

Now a rule of three applies as follows: if 80 g of SO₃ are contained in 1 mol, 835 g of the compound, how many moles are there?

$moles=\frac{835 g* 1 mole}{80 g}$

moles= 10.44

Finally, you apply a new rule of three as follows: if, according to STP, 1 mole occupies a volume of 22.4 L, 10.44 moles, how much volume does it occupy?

volume=$\frac{10.44 moles*22.4 L}{1 mole}$

volume=233.856 L

The volume of 835 g SO₃ at STP is 233.856 L