Question

The temperature of the Sun’s atmosphere near the surface is about 6000 K, and the concentration of atoms is about 1015 particles/m3. What are the average pressure and density of its atmosphere? What assumptions did you make to solve the problem?

Answer 1

Answer:

average pressure = 8.314 ×$10^{-5}$ pascal

density = 1.66 ×$10^{-12}$ kg/m³

Explanation:

given data

temperature of sun = 6000 K

concentration of atoms = $10^{15}$  particles/m³

to find out

average pressure and density of its atmosphere

solution

first we get here average pressure of  atmosphere that is express as

average pressure = $\frac{nRT}{V}$   .............1

put here value we get

average pressure = $\frac{10^15*8.314*6000}{6*10^{23}}$

average pressure = 8.314 ×$10^{-5}$ pascal

and

density of atmosphere will be

density =  $\frac{nM}{V}$   .............2

density = $\frac{10^{15}*1.66*10^{-27}}{1}$

density = 1.66 ×$10^{-12}$ kg/m³