Respuesta :
Answer:
[tex](\dfrac{11}{13},\dfrac{36}{13})[/tex].
Step-by-step explanation:
The given equation of line is
[tex]5x+y=7[/tex] .... (1)
If a line is defined as ax+by=c, then the slope of the line is -a/b.
We need to find the point on the line 5x + y = 7 that is closest to the point (−3, 2).
Draw a perpendicular line from the point (-3,2) on the line 5x + y = 7.
For the given line a=5 and b=1. So, the slope of given line is -5.
Product of slopes of two perpendicular lines is -1. Slope of given line -5, it means the slope of perpendicular line is 1/5.
The slope of perpendicular line is 1/5 and it passes through the point (-3,2). So, the equation of line is
[tex]y-y_1=m(x-x_1)[/tex]
where, m is slope.
[tex]y-2=\frac{1}{5}(x-(-3))[/tex]
Multiply both sides by 5.
[tex]5y-10=x+3[/tex]
[tex]5y-x=10+3[/tex]
[tex]5y-x=13[/tex] . .... (2)
The intersection point of line (1) and (2) is the point on the line 5x + y = 7 that is closest to the point (−3, 2).
On solving (1) and (2) we get
[tex]x=\dfrac{11}{13}, y=\dfrac{36}{13}[/tex]
Therefore, the point [tex](\dfrac{11}{13},\dfrac{36}{13})[/tex] on the line 5x + y = 7 that is closest to the point (−3, 2).
Following are the calculation to the points:
Given:
Line: [tex]5x + y = 7[/tex]
point: [tex](-3, 2)[/tex]
To find:
point=?
Solution:
Assuming the point [tex]P(h,k)[/tex] is closest to the distance from [tex]P(h,k)\ to\ (-3,2)[/tex]
[tex]D= \sqrt{(h+3)^2+(k-2)^2} \ \[/tex] using the distance formula
Equation of line:
[tex]\to 5h +k= 7 \\\\\to k= 7-5h \\\\[/tex]
Substituting the value of [tex]k=7-5h \ in\ D= \sqrt{(h+3)^2+(k-2)^2} \\\\[/tex]
[tex]D= \sqrt{(h+3)^2+(7-5h-2)^2} \\\\[/tex]
[tex]= \sqrt{(h+3)^2+(-5h+5)^2} \\\\= \sqrt{h^2+9+6h +25h^2 +25 -50h} \\\\= \sqrt{26h^2+34-44h} \\\\[/tex]
Differentitate D with respect to h
[tex]\frac{dD}{dh} =\frac{44h-34}{2 \sqrt{26h^2-44h +34}}[/tex]
Set [tex]\ \frac{dD}{dh}=0\\\\[/tex]
Then,
[tex]44h-34= 0\\\\44h=34\\\\\to h=\frac{34}{44}\=\frac{17}{22}[/tex]
So, [tex]k = 7-5h[/tex]
[tex]= 7-5 \frac{17}{22}\\\\= 7-\frac{85}{22}\\\\= \frac{154-85}{22}\\\\= \frac{69}{22}\\\\[/tex]
Therefore, the points are "[tex](\frac{69}{22}, \frac{17}{22} )[/tex]"
Learn more:
brainly.com/question/16131866