Respuesta :

Answer:

[tex](\dfrac{11}{13},\dfrac{36}{13})[/tex].

Step-by-step explanation:

The given equation of line is

[tex]5x+y=7[/tex]         .... (1)

If a line is defined as ax+by=c, then the slope of the line is -a/b.

We need to find the point on the line 5x + y = 7 that is closest to the point (−3, 2).

Draw a perpendicular line from the point (-3,2) on the line 5x + y = 7.

For the given line a=5 and b=1. So, the slope of given line is -5.

Product of slopes of two perpendicular lines is -1. Slope of given line -5, it means the slope of perpendicular line is 1/5.

The slope of perpendicular line is  1/5 and it passes through the point (-3,2). So, the equation of line is

[tex]y-y_1=m(x-x_1)[/tex]

where, m is slope.

[tex]y-2=\frac{1}{5}(x-(-3))[/tex]

Multiply both sides by 5.

[tex]5y-10=x+3[/tex]

[tex]5y-x=10+3[/tex]

[tex]5y-x=13[/tex]     .  .... (2)

The intersection point of line (1) and (2) is the point on the line 5x + y = 7 that is closest to the point (−3, 2).

On solving (1) and (2) we get

[tex]x=\dfrac{11}{13}, y=\dfrac{36}{13}[/tex]

Therefore, the point [tex](\dfrac{11}{13},\dfrac{36}{13})[/tex] on the line 5x + y = 7 that is closest to the point (−3, 2).

Following are the calculation to the points:

Given:

Line: [tex]5x + y = 7[/tex]

point: [tex](-3, 2)[/tex]

To find:

point=?

Solution:

Assuming the point [tex]P(h,k)[/tex] is closest to the distance from [tex]P(h,k)\ to\ (-3,2)[/tex]

[tex]D= \sqrt{(h+3)^2+(k-2)^2} \ \[/tex]                   using the distance formula

Equation of line:

[tex]\to 5h +k= 7 \\\\\to k= 7-5h \\\\[/tex]

Substituting the value of [tex]k=7-5h \ in\ D= \sqrt{(h+3)^2+(k-2)^2} \\\\[/tex]

[tex]D= \sqrt{(h+3)^2+(7-5h-2)^2} \\\\[/tex]

   [tex]= \sqrt{(h+3)^2+(-5h+5)^2} \\\\= \sqrt{h^2+9+6h +25h^2 +25 -50h} \\\\= \sqrt{26h^2+34-44h} \\\\[/tex]

Differentitate D with respect to h

[tex]\frac{dD}{dh} =\frac{44h-34}{2 \sqrt{26h^2-44h +34}}[/tex]

Set [tex]\ \frac{dD}{dh}=0\\\\[/tex]

Then,

[tex]44h-34= 0\\\\44h=34\\\\\to h=\frac{34}{44}\=\frac{17}{22}[/tex]

So, [tex]k = 7-5h[/tex]

         [tex]= 7-5 \frac{17}{22}\\\\= 7-\frac{85}{22}\\\\= \frac{154-85}{22}\\\\= \frac{69}{22}\\\\[/tex]

Therefore, the points are "[tex](\frac{69}{22}, \frac{17}{22} )[/tex]"

Learn more:

brainly.com/question/16131866