Question

Use the quadratic formula to find the solutions to the equation.
7- 3x+1=0

Answer 1

Answer:

B

Step-by-step explanation:

quadratic formula:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

1. find a, b, and c

a = 1

b = -3

c = 1

2. plug values into formula

x = [3 ± sqrt(9-4•1•1)] / 2

3. simplify

x = [3 ± sqrt(5)] / 2

This is B.

Answer 2

Answer:

Option b) is correct

ie., $x=\frac{3\pm \sqrt{5}}{2}$

Step-by-step explanation:

Given quadratic equation is $x^{2}-3x+1=0$

To find the solutions of given equation:

Solution of quadratic equation $ax^{2}+bx+c=0$

$x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ where a,b, are coefficients of $x^{2}$ and x respectively and c is constant.

From the given quadratic equation a=1, b=-3 and c=1

$x=\frac{-(-3)\pm \sqrt{(-3)^{2}-4(1)(1)}}{2(1)}$

$x=\frac{3\pm \sqrt{9-4}}{2}$

$x=\frac{3\pm \sqrt{5}}{2}$

Therefore Option b) is correct

ie., $x=\frac{3\pm \sqrt{5}}{2}$